If K+ channels are partly blocked, then much of the K+ pumped into the cell from Na+/K+ pump would stay inside. This means the electrical gradient of the cell would be a lot less negative than normal, but should still be a bit negative from proteins. This means it would take less depolarization to trigger an action potential.
Those two statements cannot both be true. The conjugate base of a weak acid is a strong base. Since HF is a weak acid, F- is a strong base, and there will be very little HF made.
No, your statement in bold is incorrect, and this is a concept that most people get wrong. The conjugate base of a weak acid is a weak base. The conjugate base of a strong acid is a VERY weak base. HF is a weak acid, and therefore F- is a weak base. If F- was a strong base, it would mean that almost all F- would become HF meaning HF would be a VERY weak acid, which is not true - HF is a weak acid, not very weak. Something like Cl- would be a very weak base.
Or look at it this way, a weak acid dissociates somewhat, meaning there is some acid and some of its conjugate base. Since there's some of each, they are both weak.
I think it's because, at least partly, smaller group 2 ions have a smaller atomic radii and therefore the positive charge in their nuclei attracts the negative hydroxide more hence it wants to stay in its non-dissociated form. Larger smaller group 2 ions on the other hand attracts negative charges less and therefore more happy to be an ion.
Hi, I have a chemistry question about nomenclature. What is the IUPAC name for the the following compound: 2 fused hexane rings (i.e. they share a common side, total 10 carbons) with a Cl molecule attached to a carbon 1 carbon away from the fused side. If anyone is confused by this I can draw a picture.
The answer the book has is below, but I have no clue why and I have an inkling that is wrong.
7-chloro [4.3.0] nonane. And what does the [4.3.0] mean?
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bleh
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i.e. mgh = 1/2 mv^2 ==> h = v^2 / 2g
If K+ channels are partly blocked, then much of the K+ pumped into the cell from Na+/K+ pump would stay inside. This means the electrical gradient of the cell would be a lot less negative than normal, but should still be a bit negative from proteins. This means it would take less depolarization to trigger an action potential.
(n-1)! [(n+1)! - n!]
= [(n-1)!^2][(n+1)(n) - (n)] (factor out (n-1)! from second factor)
= [(n-1)!^2][n^2] (simplify second factor)
= [(n)(n-1)!]^2 (move the exponent outside)
= n!^2
No, your statement in bold is incorrect, and this is a concept that most people get wrong. The conjugate base of a weak acid is a weak base. The conjugate base of a strong acid is a VERY weak base. HF is a weak acid, and therefore F- is a weak base. If F- was a strong base, it would mean that almost all F- would become HF meaning HF would be a VERY weak acid, which is not true - HF is a weak acid, not very weak. Something like Cl- would be a very weak base.
Or look at it this way, a weak acid dissociates somewhat, meaning there is some acid and some of its conjugate base. Since there's some of each, they are both weak.
The answer the book has is below, but I have no clue why and I have an inkling that is wrong.